Answer:
[tex]\boxed{\text{24.9 L}}[/tex]
Explanation:
This looks like a case where we can use the Ideal Gas Law to calculate the volume.
pV = nRT
Data:
p = 400.0 kPa
n = 4.00 mol
R = 8.314 kPa·L·K⁻¹mol⁻¹
T = 300.0 K
Calculations:
400.0 × V = 4.00 × 8.314 × 300.0
400.0V = 9977
V = 24.9 L
[tex]\boxed{\textbf{The volume of the gas is 24.9 L.}}[/tex]
