Answer:
16.27 g.
Explanation:
- It is known that every 1.0 mol of a compound contains Avogadro's no. of molecules (6.022 x 10²³).
Using cross multiplication:
1.0 mol of N₂ gas contains → 6.022 x 10²³ molecules.
??? mol of N₂ gas contains → 3.50 x 10²³ molecules.
∴ The no. of moles of N₂ gas = (1.0 mol)(3.50 x 10²³ molecules)/(6.022 x 10²³ molecules) = 0.5812 mol.
∴ The mass of 3.50 x 10²³ molecules of N₂ gas = (no. of moles)*(molar mass) = (0.5812 mol)(28.0 g/mol) = 16.27 g.
