A 32 gram sample of a substance that’s a by-product of fireworks has a k-value of 0.1368. Find the substance’s half-life, in days. Use formula
N=N0e-kt, t= time in days.
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Respuesta :

Answer:

t=5.1 days

Step-by-step explanation:

We know that the formula is:

[tex]N = N_0e^{-kt}[/tex]

Where N is the amount of substance after a time t, [tex]N_0[/tex] is the initial amount of substance, k is the rate of decrease, t is the time in days.

[tex]k=0.1368\\N_0 =32[/tex]

We want to find the average life of the substance in days

The half-life of the substance is the time it takes for half the substance to disintegrate.

Then we equal N to 16 gr and solve the equation for t

[tex]16= 32e^{-0.1368t}[/tex]

[tex]0.5= e^{-0.1368t}[/tex]

[tex]ln(0.5)= ln(e^{-0.1368t})[/tex]

[tex]ln(0.5)= -0.1368t[/tex]

[tex]t= \frac{ln(0.5)}{-0.1368}\\\\t=5.1\ days[/tex]

Answer:

5.1

PLATO answer

Step-by-step explanation: