Respuesta :

superman1987

Answer:

0.2 M.

Explanation:

  • For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

∴ (XMV) KOH = (XMV) H₂SO₄.

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

  • For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

  • For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

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