Answer:
x_1= √-28/-2
x_2= 2 + √-28
Quadratic formula method: ↓
Step-by-step explanation:
Given) 2x + 3 - x² - 1 * 4
1) Communtative Property: 2x + 3 - x² - 1 * 4 = -x² - 1 * 4 + 2x + 3
2) Communtative Property: -x² - 1 * 4 + 2x + 3 = -x² + 2x - 1 * 4 + 3
3) Communtative Property: 2x - x² - 1 * 4 + 3
4) Solve: 2x - x² - 1 * 4 + 3
5) Solve: 2x - x² - 4 + 3
6) 2x - x² - 7
7) Communtative Property: -x² + 2x - 7
8a) Quadratic Formula: ax²+bx+c=0; x = ((-b)± √(b²-4ac))/2a
8b) Let -1=a, let 2=b, let -7=c
9a) Substitute -1 for a: x = ((-b)± √(b²-4(-1)c))/2(-1)
9b) Substitute 2 for b: x = ((-2)± √(2²-4(-1)c))/2(-1)
9c) Substitute -7 for c: x = ((-2)± √(2²-4(-1)(-7))/2(-1)
10a) Solve: (-2± √2²-4(-1)(-7))/-2 = (-2± √4 -4(-1)(-7))/-2
10b) Solve: (-2± √4 -4(-1)(-7))/2(-1) = (-2± √4+ -4(-1)(-7))/-2
11) Solve: (-2± √4 + -4(-1)(-7))/-2 = (-2± √4 + (4)(-7))/-2 = (-2± √4 + -28)/-2
12) Solve: (-2± √4 + √-28)/-2 = (-2± 2 + √-28)/-2
13a) Solve 1 way: (-2+ 2 + √-28)/-2 = (0 + √-28)/-2 =
x_1= √-28/-2
13b) Solve 2 way: (-2- 2 + √-28)/-2 = (-4 + √-28)/-2 =
x_2= 2 + √-28
14) Or solve a different way... I'm pretty sure theres another, more accurate way to solve this. :(
I hope I helped. I wasn't very sure on how to do this though, sorry if I am wrong. :(
