Hello!
The answer is:
The simplified expression is:
[tex](x + y + 3)(x + y - 4)=x^{2} +y^{2} +2xy-x-y-12[/tex]
Why?
To solve the problem, we need to remember how to use the distributive property and how to add like terms.
The distributive property can be defined as follow:
[tex](a+b)(c+d)=ab+ad+bc+bd[/tex]
The like terms are the terms that share the same variable and the same exponent, for example:
[tex]3x+x+ x^{2}=x^{2} +4x[/tex]
We were able to add the first and the second term because they share the same variable and the same exponent.
Now, we are given the expression:
[tex](x+y+3)(x+y-4)[/tex]
So, simplifying we have:
[tex](x + y + 3)(x + y - 4)=(x*x)+(x*y)-(4*x)+(y*x)+(y*y)-(4*y)+(3*x)+(3*y)-(3*4)\\\\(x + y + 3)(x + y - 4)=x^{2} +xy-4x+xy+y^{2}-4y+3x+3y-12\\\\(x + y + 3)(x + y - 4)=x^{2} +y^{2} +2xy-x-y-12[/tex]
Hence, we have that the simplified expression is:
[tex](x + y + 3)(x + y - 4)=x^{2} +y^{2} +2xy-x-y-12[/tex]
Have a nice day!
