Answer:
[tex]8.4\cdot 10^7 N[/tex]
Explanation:
The electrostatic force between two objects is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
In this problem, we have two boxes separated by
[tex]r = 1\cdot 10^6 m[/tex]
The first box contains [tex]6.02\cdot 10^{23}[/tex] protons, so its charge is:
[tex]q_1 = (6.02\cdot 10^{23})(1.6\cdot 10^{-19} C)=9.63\cdot 10^4 C[/tex]
The second box contains [tex]6.02\cdot 10^{23}[/tex] electrons, so its charge is:
[tex]q_2 = (6.02\cdot 10^{23})(-1.6\cdot 10^{-19} C)=-9.63\cdot 10^4 C[/tex]
We are only interested in the magnitude of the force, so we can neglect the negative sign and calculate the electrostatic force as:
[tex]F=(9\cdot 10^9) \frac{(9.63\cdot 10^4 C)(9.63\cdot 10^4 C)}{(1\cdot 10^6 m)^2}=8.4\cdot 10^7 N[/tex]
