Write an equation for the line that is parallel to the given line and that passes through the given point. y = 5/2 x – 10; (–6, –29)

Respuesta :

Answer:  [tex]y=\frac{5}{2}x-14[/tex]

Step-by-step explanation:

The equation of the line in slope-intercept form is:

[tex]y=mx+b[/tex]

Where m is the slope and b the intersection with the y-axis.

You know the line [tex]y=\frac{5}{2}x-10[/tex]

You can identify that:

[tex]m=\frac{5}{2}[/tex]

The slopes of Parallel lines are equal, then the slope of the other line is  [tex]m=\frac{5}{2}[/tex]

Substitute the slope and the given point into [tex]y=mx+b[/tex] and solve for b:

[tex]-29=\frac{5}{2}(-6)+b\\-29=-15+b\\-29+15=b\\b=-14[/tex]

Substituting values, you get that the equation of this line is:

 [tex]y=\frac{5}{2}x-14[/tex]