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Mr. Clarke built a deck around the swimming pool and sandbox in his backyard. What is the area of the decking that surrounds the pool and sandbox, rounded to the nearest tenth of a square foot?

Mr Clarke built a deck around the swimming pool and sandbox in his backyard What is the area of the decking that surrounds the pool and sandbox rounded to the n class=

Respuesta :

calculista

Answer:

[tex]1,174.8\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of the decking is equal to the area of the parallelogram minus the area of the pool minus the area of the sand box

Remember that

[tex]21\frac{1}{2}\ ft=21.5\ ft[/tex]

so

[tex]A=(50)(35)-(20)(25)-(21.5)(7)/2\\A= 1,750-500-75.25\\A=1,174.8\ ft^{2}[/tex]

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