Respuesta :

Start with

[tex]6-\dfrac{2}{3}x<x-9[/tex]

Add 9 to both sides

[tex]15-\dfrac{2}{3}x<x[/tex]

Add [tex]\frac{2}{3}x[/tex] to both sides

[tex]15<\dfrac{5}{3}x[/tex]

Multiply both sides by 3/5

[tex]9<x[/tex]

Which is the same as

[tex]x>9[/tex]

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