Respuesta :

Answer:

B) irrational

Step-by-step explanation:

It can not be imaginary, because imaginary numbers are √(negative number).

It can not be rational, because the cube root of 11 can not be displayed as a repeating or ending number (it's 2.22398009... by the way).

The only option is irrational.

tramserran

Answer:   irrational

Step-by-step explanation:

[tex]\sqrt[3]{11} = 2.2239800905693152........\\\\\text{It has a decimal that never terminates (ends) or r e p e a t s, so it is an}\\\text{irrational number.}[/tex]

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