Answer:
[tex]1.8\cdot 10^{-11} N[/tex]
Explanation:
The force acting on the electron due to the magnetic field is
[tex]F=qvB sin \theta[/tex]
where
[tex]q=1.6\cdot 10^{-19} C[/tex] is the charge of the electron
[tex]v=2.5\cdot 10^7 m/s[/tex] is its speed
[tex]B=4.4 T[/tex] is the intensity of the magnetic field
[tex]\theta=90^{\circ}[/tex] is the angle between the direction of the field and the velocity of the electron
Substituting all the numbers into the equation, we find
[tex]F=(1.6\cdot 10^{-19}C)(2.5\cdot 10^7 m/s)(4.4 T) sin 90^{\circ}=1.8\cdot 10^{-11} N[/tex]
