Answer: a. 1
Step-by-step explanation:
[tex]\sqrt{2x+7}+1=\sqrt{2x+14}\\\\(\sqrt{2x+7}+1)^2=(\sqrt{2x+14})^2\\\\2x+7+2\sqrt{2x+7}+1=2x+14\\\\2x+8+2\sqrt{2x+7}=2x+14\\\\2\sqrt{2x+7}=6\\\\\sqrt{2x+7}=3\\\\(\sqrt{2x+7})^2=(3)^2\\\\2x+7=9\\\\2x=2\\\\x=1\\\\\\Check:\\\sqrt{2(1)+7}+1=\sqrt{2(1)+14}\\\\\sqrt9+1=\sqrt16\\\\3+1=4\ \checkmark[/tex]
