Answer:
Part a) In the procedure
Part b) Line A and Line B are different parallel lines
Step-by-step explanation:
Part a) we have
[tex]3x-6y=-12[/tex] ----> equation A
[tex]x-2y=-8[/tex] ----> equation B
Isolate the variable x in the equation B
[tex]x=2y-8[/tex]
Substitute the value of x in the equation A
[tex]3(2y-8)-6y=-12[/tex]
[tex]6y-24-6y=-12[/tex]
[tex]-24=-12[/tex] ------> is not true
therefore
The system of equations has no solutions
Part b) What do you know about the two lines in this system of equations?
[tex]3x-6y=-12[/tex] ------> equation A
isolate the variable y
[tex]6y=3x+12[/tex]
[tex]y=(1/2)x+2[/tex]
[tex]x-2y=-8[/tex] -------> equation B
isolate the variable y
[tex]2y=x+8[/tex]
[tex]y=(1/2)x+4[/tex]
Line A and Line B are parallel lines, because their slopes are the same
Line A and Line B are different lines because their y-intercept is not the same