Answer:
1.65 N
Explanation:
The force applied on the spring is given by Hook's Law:
[tex]F=k \Delta x[/tex]
where
k = 30 N/m is the spring constant
[tex]\Delta x = 19.5 cm - 14 cm = 5.5 cm = 0.055 m[/tex] is the elongation of the spring relative to its initial position
Substituting the numbers into the equation, we find the force applied to the spring:
[tex]F=(30 N/m)(0.055 m)=1.65 N[/tex]
