Answer:
KPF = 9 and H = 129
Step-by-step explanation:
An inscribed quadrilateral in a circle has all diagonal angles add up to 180, so we can use this to find the angles of the quadrilateral.
H= 180-EPK and K = 180-E so H = 129 and K = 60
Now PF and EH are parallel, so PE is a transversal. That means FPE = 180 - E = 60. Now it's pretty easy to solve for KPF = FPE - EPK = 60 - 51 = 9.
Let me know if you don't see how I did any of this and I'll be happy to explain it..
