Answer:
[tex]\large\boxed{C.\ \left(\dfrac{14}{3},\ 0\right)}[/tex]
Step-by-step explanation:
[tex]\text{The x-intercept is for y = 0.}\\\\\text{Put y= 0 to the equation}\ 3x + 3y = 14:\\\\3x + 3(0) = 14\\\\3x + 0 = 14\\\\3x = 14\qquad\text{divide both sides by 3}\\\\x =\dfrac{14}{3}[/tex]
