Tristan rode his bike 3 2/3 miles on Saturday he rode 1 4/5 Mi on Sunday how many more miles did he ride on Saturday then on Sunday a.1 3/15 Miles b.1 3/5 c.1 13/15 d.2 13/15​

Respuesta :

Answer:

c. 1 13/15

Step-by-step explanation:

The best way to find out how much more Tristan rode his bike would be to subtract both of his distances together.

Saturday = [tex]3\dfrac{2}{3}[/tex]

Sunday = [tex]1\dfrac{4}{5}[/tex]

Now we actually have two different fractions with different denominators.

We can solve this first by converting the mixed numbers into improper fractions.

[tex]3\dfrac{2}{3}=\dfrac{9+2}{3}[/tex]

[tex]3\dfrac{2}{3}=\dfrac{11}{3}[/tex]

Now how did I do that?

First we take the denominator and multiply it to our whole number, then add the product to the numerator.

Let's proceed to the next mixed fraction.

[tex]1\dfrac{4}{5}=\dfrac{5+4}{5}[/tex]

[tex]1\dfrac{4}{5}=\dfrac{9}{5}[/tex]

We are then left with:

[tex]\dfrac{11}{3}-\dfrac{9}{5}[/tex]

Since we cannot subtract them directly because they have different denominators, we need to find the LCD of both denominators.

[tex](\dfrac{5}{5}) \dfrac{11}{3}-\dfrac{9}{5}(\dfrac{3}{3})[/tex]

[tex]\dfrac{55}{15}-\dfrac{27}{15}[/tex]

Now that they have similar denominators, we can then proceed to subtract them to each other.

[tex]\dfrac{55}{15}-\dfrac{27}{15}=\dfrac{28}{15}or1\dfrac{13}{15}[/tex]