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For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and diameter of the circle? c) graph.

Respuesta :

gmany

Answer:

a) center (2, -3)

b) radius r = 3

c) in the attachment

Step-by-step explanation:

The standard form of an equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have:

[tex](x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2[/tex]

a) center (2, -3)

b) radius r = 3

c) in the attachment

Ver imagen gmany
facundo3141592

The answers are:

  • a) The point (2, -3).
  • b) The radius is 3 units, and the diameter is 6 units.
  • c) The graph can be seen below.

What is the equation of a circle?

The equation of a circle centered in the point (a, b) of radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Then for the equation:

(x-2)^2+(y+3)^2 = 9 = 3^2

We can see that:

a) The center is the point (2, -3)

b) The radius is R = 3, and the diameter is twice the radius, so it is equal to 6.

c) The graph can be seen below:

If you want to learn more about circles, you can read:

https://brainly.com/question/1559324

Ver imagen facundo3141592

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