Answer:
[tex]3.38\cdot 10^6 m/s[/tex]
Explanation:
Assuming the electron is moving in a straight line, it means that the electric force and the magnetic force acting on the electron are balanced:
[tex]F_E = F_B\\qE = qvB[/tex]
where
q is the electron charge
E is the electric field
v is the electron speed
B is the magnetic field
Re-arranging the equation and solving for v, we find the electron's speed:
[tex]v=\frac{E}{B}=\frac{1.56\cdot 10^4 V/m}{4.62\cdot 10^{-3} T}=3.38\cdot 10^6 m/s[/tex]
