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I WILL AWARD BRAINLIEST!! PLEASE HELP!!!
In △ABC, ∠B = 90°, BH = AH, and the ratio of m∠A to m∠C is 1:2. Find m∠BHA?
A. 100°
B. 90°
C. 120°
D. 60°

I WILL AWARD BRAINLIEST PLEASE HELP In ABC B 90 BH AH and the ratio of mA to mC is 12 Find mBHA A 100 B 90 C 120 D 60 class=

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wegnerkolmp2741o

Answer:

C. 120°

Step-by-step explanation:

Let angle A be x, then angle C is 2x

The sum of the angles in ABC is

A + B+ C = 180

x+90 +2x = 180

3x +90 = 180

3x= 90

Divide by 3

x = 90/3

x = 30

Angle A = 30,  Angle C = 2x = 60

AH = BH, so it is an isosceles triangle .  That means A and ABH are equal

A = 30 , ABH = 30

The sum of the angles in ABH must equal 180

A + ABH + BHA = 180

30 + 30 + BHA = 180

60 + BHA = 180

BHA = 180-60

BHA = 120

Answer:

C

Step-by-step explanation:

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