A binding protein binds to a ligand l with a kd of 400 nm. what is the concentration of ligand when y is (a) 0.25, (b) 0.6, (c) 0.95?

Respuesta :

Hey there!:

The fractional saturation y is defined as :

y =  [ L ] / Kd + [ L ]

where :

[ L ] = concentration of binding ligand

Kd = 400 nm

Ver imagen Willchemistry
Lanuel

The concentration of ligand are:

a. 133.33 Nm.

b. 600 Nm.

c. 7,600 Nm.

Given the following data:

  • Dissociation constant, Kd = 400 Nm

To find the concentration of ligand, we would use the fractional saturation formula.

Fractional saturation (Y) is expressed as a ratio of protein with bound ligand to that of the total protein concentration.

Mathematically, fractional saturation (Y) is given by the formula;

[tex]Y = \frac{A}{K_d \;+ \;A}[/tex]

Where:

  • Y is fractional saturation.
  • A is the binding ligand concentration.
  • Kd is the dissociation constant.

a. To find A, when Y = 0.25;

[tex]0.25 = \frac{A}{400 \;+ \;A}[/tex]

Cross-multiplying, we have:

[tex]0.25(400\; + \;A) = A\\\\100 + 0.25A = A\\\\A - 0.25A = 100\\\\0.75A = 100\\\\A = \frac{100}{0.75}[/tex]

A = 133.33 Nm

b. To find A, when Y = 0.6;

[tex]0.6 = \frac{A}{400 \;+ \;A}[/tex]

Cross-multiplying, we have:

[tex]0.6(400\; + \;A) = A\\\\240 + 0.6A = A\\\\A - 0.6A = 240\\\\0.4A = 240\\\\A = \frac{240}{0.4}[/tex]

A = 600 Nm

c. To find A, when Y = 0.95;

[tex]0.95 = \frac{A}{400 \;+ \;A}[/tex]

Cross-multiplying, we have:

[tex]0.95(400\; + \;A) = A\\\\380 + 0.95A = A\\\\A - 0.95A = 380\\\\0.05A = 380\\\\A = \frac{380}{0.05}[/tex]

A = 7,600 Nm

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