A circle is centered at P(0,0). The point W(-6, √37) is on the circle. Where does the point Z(8,3) lie?

Inside the circle, on the circle, Outside the circle

Respuesta :

Answer:

On the circle

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

The radius is the distance from the centre to a point on the circle.

To calculate r use the distance formula

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 6, [tex]\sqrt{37}[/tex])

r = [tex]\sqrt{(-6-0)^2+(\sqrt{37-0)^2} }[/tex]

  = [tex]\sqrt{36+37}[/tex] = [tex]\sqrt{73}[/tex]

Hence

x² + y² = ([tex]\sqrt{73}[/tex])²

x² + y² = 73 ← equation of circle

Substitute (8, 3) into the left side of the equation and

value < 73 → lies inside circle

value = 73 ← lies on the circle

value > 73 ← lies outside circle

(8, 3) → 8² + 3² = 64 + 9 = 73

(8, 3) lies on the circle

Answer:

On the Circle

Step-by-step explanation:

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