Respuesta :

carlosego

Answer: Option a.

Step-by-step explanation:

By definition, a functioon is even when:

[tex]f(x)=f(-x)[/tex]

And it is odd when:

[tex]-f(x)=f(-x)[/tex]

Therefore, you can verify if the function is even substituting -x into the function:

[tex]f(-x)=2(-x)^{4}+2(-x)^{2}\\f(-x)=2x^{4}+2x^{2}[/tex]

Then:

[tex]-f(x)=f(-x)[/tex]

It is an even function.

zainebamir540

Answer:

Choice A is correct.

Step-by-step explanation:

We have  given a function.

y = 2x⁴ +2x²

suppose y = f(x) , we get,

f(x) =  2x⁴ +2x²

We have to find that is this function is even or  odd?

A function is even if f(x) = f( -x).

A function is odd if f(x) = - f(x).

Putting x = -x in f(x) we get,

f(-x) = 2(-x)⁴+2(-x)²

f(-x)  = 2x⁴+2x²

f(-x) = f(x)

So, the function is even.

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