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You are given an original figure with coordinates B(-7,-2), A(5,-2), and D(-7,7) and its image with coordinates J(-3,0), K(1,0), L(-3,3).

You are given an original figure with coordinates B72 A52 and D77 and its image with coordinates J30 K10 L33 class=

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wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

DB = 9  units  (by counting)

BA = 12 units  (by counting)

DA  can be found by using the pythagorean theorem

a^2 +b^2 = c^2

BD^2 + BA^2 = DA ^2

9^2 +12^2 = DA^2

81 +144 = DA^2

225 = DA ^2

Take the square root of each side

sqrt(225) = sqrt(DA^2)

15 = DA

LJ = 3  units  (by counting)

JK = 4 units  (by counting)

LK  can be found by using the pythagorean theorem

a^2 +b^2 = c^2

LJ^2 + JK^2 = LK ^2

3^2 +4^2 = LK^2

9 +116 = LK^2

25 = LK ^2

Take the square root of each side

sqrt(25) = sqrt(LK^2)

5 = LK

Scale factor from BAD to JKL

15 to 5

Divide each side by 5

3 to 1

We multiply by 1/3 to go from the big to small

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