Answer:
Option D. [tex]25\ students\ in\ cooking\ club[/tex]
Step-by-step explanation:
Let
x-----> the number of students in art club
y-----> the number of students in drama club
z-----> the number of students in cooking club
we know that
[tex]\frac{x}{y} =\frac{7}{13}[/tex]
[tex]x=\frac{7}{13}y[/tex] -----> equation A
[tex]\frac{z}{x}=\frac{5}{14}[/tex]
[tex]z=\frac{5}{14}x[/tex] -----> equation B
[tex]y=130\ students\ in\ drama\ club[/tex]
step 1
Substitute the value of y in equation A and solve for x
[tex]x=\frac{7}{13}(130)=70\ students\ in\ art\ club[/tex]
step 2
substitute the value of x in equation B and solve for z
[tex]z=\frac{5}{14}(70)=25\ students\ in\ cooking\ club[/tex]
