Answer: The freezing point of water will decrease by 7.44 K.
Explanation
Moles of sugar = 4 moles
Mass of water = 1 kg
i = van't Hoff factor of sugar = 1
[tex]K_f= 1.86 K kg/mol[/tex]
[tex]\Delta T_f=ik_f\times molality[/tex]
[tex]\Delta T_f=1\times 1.86 K kg/mol\times \frac{4 mol}{1 kg}=7.44 K[/tex]
[tex]\Delta T_f=7.44 K[/tex]
The freezing point of water will decrease by 7.44 K. .
