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A business uses straight-line depreciation to determine the value of an automobile over a 6-year period. Suppose the original value (when t=0) is equal to $17,400 and the salvage value (when t=6) is equal to $3000. Write the linear equation that models the value, s, of this automobile at the end of year t.

Respuesta :

JeanaShupp

Answer: [tex]s=17400-2400t[/tex]

Step-by-step explanation:

Since it is a case of depreciation, there for the rate of change in the price of automobile should be negative.

The rate of change of this linear function is given by:-

[tex]m=\frac{\text{salvage value}-\text{original value}}{t_6-t_0}\\\Rightarrow\ m=\frac{3000-17400}{6-0}\\\Rightarrow\ m=\frac{-14400}{6}\\\Rightarrow\ m=-2400[/tex]

Thus, the original value of automobile depriciates by rate of $2400 per year.

The the linear equation that models the value, s, of this automobile at the end of year t is given by:-

[tex]s=17400-2400t[/tex]

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