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If an object is projected upward with an initial velocity of 126ft per? sec, its height h after t seconds is h=?16t^2+126t. Find the height of the object after 4 seconds

Respuesta :

wegnerkolmp2741o

Answer:

=760 ft

Step-by-step explanation:

h=16t^2+126t

Let t=4

h = 16 (4)^2 +126(4)

h = 16*16 +126(4)

  =256+504

   =760 ft

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