Answer:
The height of the rocket = 43.49 yards.
Step-by-step explanation:
For better understanding of the solution, see the attached figure :
Let donate the angle of elevation by θ , it is the angle formed between the horizontal and the line of sight.
The height of the rocket will be perpendicular to the ground so a right angled triangle can be formed as shown in the figure.
Now, in ΔABC
[tex]\tan\theta=\frac{Perpendicular}{Base}\\\\\tan 46\degrees=\frac{AB}{42}\\\\\implies AB=\tan 46\degrees\times 42\\\\\bf\implies AB=43.49\thinspace{ yards}[/tex]
Hence, The height of the rocket = 43.49 yards.
