Answer:
[tex]\frac{1}{9}x+\frac{47}{9}=\frac{1}{9}(x+47)[/tex]
Step-by-step explanation:
we are given
[tex]\frac{1}{9}x+\frac{47}{9}[/tex]
Since, we have to factor out 1/9
so, firstly we will factor it in terms of 1/9
[tex]\frac{1}{9}\times x+\frac{1}{9}\times 47[/tex]
we can see that
both terms have 1/9
so, we can factor out 1/9
and we get
[tex]\frac{1}{9}(x+47)[/tex]
so, we will get after factoring as
[tex]\frac{1}{9}x+\frac{47}{9}=\frac{1}{9}(x+47)[/tex]
