Answer:
Step-by-step explanation:
Given: [tex]GF=\frac{1}{2}GC[/tex],
[tex]GE=\frac{1}{2}GD[/tex] and [tex]EF=\frac{1}{2}DC[/tex]
To prove: ΔGFE is similar to ΔGCD.
Proof: Since, [tex]\frac{GF}{GC}=\frac{1}{2}[/tex], [tex]\frac{GE}{GD}=\frac{1}{2}[/tex] and [tex]\frac{EF}{DC}=\frac{1}{2}[/tex], therefore
[tex]\frac{GF}{GC}=\frac{GE}{GD}=\frac{EF}{DC}[/tex]
Hence, by transitive property of equality, ΔGFE is similar to ΔGCD.
