niktadutta101 niktadutta101

28-01-2019
Mathematics

contestada

Suppose DK is an angle bisector of △DEF. Given: EK=2, FK=5, DF=10. Find DE.

Respuesta :

sqdancefan sqdancefan

01-02-2019

Answer:

DE = 4

Step-by-step explanation:

The bisector divides the triangle into proportional segments, so ...

FK/DF = EK/DE

5/10 = 2/DE . . . . substitute given values

DE = 4 . . . . . multiply by 2DE

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