Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40 units to test for quality. The product is put through a wear-and-tear test to determine the number of days it can last. If the product has a lifespan of less than 26 days, it is considered defective. The table gives the sample data that a quality control manager collected.

The point estimate of the mean of the sample is _, and the point proportion of the defective units is _

(Give your answers as decimal numbers rounded off to the nearest hundredth.)

Question

27-01-2019
Physics

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40 units to test for quality. The product is put through a wear-and-tear test to determine the number of days it can last. If the product has a lifespan of less than 26 days, it is considered defective. The table gives the sample data that a quality control manager collected.

The point estimate of the mean of the sample is _, and the point proportion of the defective units is _

(Give your answers as decimal numbers rounded off to the nearest hundredth.)

$Type the correct answer in each box Use numerals instead of words If necessary use for the fraction barsA company manufactures 2000 units of its flagship produc class=$

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IlaMends IlaMends · Answer 1 · 2019-01-30T07:03:11+01:00

Answer: The mean of the samples is 32.325.

Proportion of the defective unit is =[tex]\frac{2}{40}=\frac{1}{20}=0.05[/tex]

Explanation:

The point estimate of the mean of the sample:

First calculate the mean of the 40 samples:

[tex]\frac{\text{Sum of all the samples}}{\text{Number of observations}}[/tex]

[tex]\frac{1,293}{40}=32.325[/tex]

The mean of the samples is 32.325.

Defected pieces in the samples whose life span is less than the 26 days = 2

Proportion of the defective unit is =[tex]\frac{2}{40}=\frac{1}{20}=0.05[/tex]

zitterkoph zitterkoph · Answer 2 · 2019-05-15T16:45:46+02:00

zitterkoph zitterkoph

15-05-2019

Answer:

The point estimate of the mean of the sample is 32.3 , and the point proportion of the defective units is 0.05 .

Explanation:

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