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0.1 gram mixture of solid substances containg sodium hydroxide and sodium chloride was titrated with 0.1 molar hydrochloric acid the complete reaction takes place by consumption of 10 mlof the acid calculate the percentage of sodium hydroxide in the mixture

Respuesta :

No of moles of HCl = 0.1 x 10/1000 = 0.001 mole
NaOH+ HCl ——> NaCl + h2O
No of moles of HCl = no of moles of NaOH
Molar mass of NaOH = 23 + 16 + 1=40g
Mass of NaOH = no of moles x molar mass = 0.001 x 40=0.04g
Percentage = 0.04/0.1 x100=40%

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