24 Doughnut will be eaten by 8 students in 9 minutes. 8 monkeys will eat 6 bananas in 6 mins.
Given,
Two students can eat 4 doughnuts in 6 minutes.
On taking time constant (say 6 min), 2 student eat 4 doughnuts,
So 1 student eat 2 doughnuts each in 6 minutes.
So, in 1 minute doughnut eaten by 1 student will be [tex]\frac{2}{6}[/tex].
So, in 9 minute doughnut eaten by 1 student will be [tex](\frac{2}{6} \times 9=3)[/tex]
Finally, in 9 minute doughnut eaten by 8 student will be [tex](3\times 8=24)[/tex].
Hence 24 Doughnut will be eaten by 8 students in 9 minutes.
Similarly,
Since 8 monkeys eat 8 bananas in 8 mins.
On taking time constant, 8 monkeys eat 8 bananas.
So, 1 monkey eat 1 banana in 8 min.
So, in 1 min 1 monkey will eat [tex](\frac{1}{8} )[/tex] banana.
So, 1 banana will be eaten by 8 monkeys in 1 min.
So, 6 banana will be eaten by [tex](8\times 6=48)[/tex] monkeys in 1 min.
Finally, the number of monkeys required to eat 6 bananas in 6 min will be,
[tex]\dfrac{48}{6} =8[/tex].
Therefore 8 monkeys will eat 6 bananas in 6 mins.
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https://brainly.com/question/12116123
