Respuesta :
Steps
So firstly, we need to isolate the x terms onto one side. To do this, subtract 48 on both sides of the equation:
[tex]2x^2-20x=-48[/tex]
Next, divide both sides by 2:
[tex]x^2-10x=-24[/tex]
Next, we are gonna make the left side of the equation a perfect square. To find the constant of this soon-to-be perfect square, divide the x coefficient by 2 and then square the quotient. Add the result onto both sides of the equation:
[tex]-10 \div 2=-5\\(-5)^2=25\\\\x^2-10x+25=1[/tex]
Now, factor the left side:
[tex](x-5)^2=1[/tex]
Next, square root both sides of the equation:
[tex]x-5=\pm 1[/tex]
Next, add 5 to both sides of the equation:
[tex]x=5\pm 1[/tex]
Lastly, solve the left side twice -- once with the plus sign and once with the minus sign.
[tex]x=6,4[/tex]
Answer
In short, x = 6 and 4
Answer: x = 4 x = 6
Step-by-step explanation:
2x² - 20x + 48 = 0
2x² - 20 x + _____ = -48 + ______ subtracted 48 from both sides
2(x² - 10x + _____ ) = 2(-24 + _____ ) factored out 2 from both sides
x² - 10x + _____ = -24 + _____ divided both sides by 2
x² - 10x + 25 = -24 +25 added 25 to both sides
↓ ↑ ↑
[tex]\dfrac{-10}{2}=(-5)^2[/tex] [tex]\bigg(\dfrac{b}{2}\bigg)^2[/tex] makes a perfect square
(x - 5)² = 1 simplified
[tex]\sqrt{(x-5)^2} =\sqrt{1}[/tex] took square root of both sides
x - 5 = ± 1 simplified
x - 5 = 1 x - 5 = -1 split into two separate equations
x = 6 x = 4 solved for x