Answer:
None of these
Step-by-step explanation:
y-5\√(2y2 - 7y -15)
On simplifying 2y2 - 7y -15, we get
2y2 – (10-3)y -15
= 2y2 – 10y -3y-15
= 2y(y-5)-3(y-5)
= (2y-3)(y-5)
On squaring nominator and denominator we get
(y-5)2/(2y-3)(y-5)
= (y-5)/(2y-3)
So the quotient becomes, 5/2
While the remainder becomes 2.5
