a = (Vf - Vi) / t = (13.9 m/s - 0 m/s) / 10 s = 1.4 m/s^2
Answer:
Acceleration of the bus is 1.38 m/s^2
Explanation:
Given that,
Initial speed of the bus, u = 0 m/s (rest)
Final speed of the bus, v = 50 km/h
or v = 13.88 m/s
Time taken, t = 10 s
To find :
The magnitude of the acceleration of the car.
Solve :
Let a is the acceleration of the car. The rate of change of velocity is called the acceleration of the bus. Its formula is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{(13.88-0)\ m/s}{10\ s}[/tex]
[tex]a=1.38\ m/s^2[/tex]
Therefore, the magnitude of the car's acceleration is 1.38 m/s^2.
