myahgoss
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What are the x and y intercepts of the equation y=log(3x+3)-2


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Respuesta :

SFM19613

[tex]y \: = \: log(3x \: + \: 3) \: - \: 2[/tex]
For x-intercept,
y = 0,
log(3x+3) = 2
(3x + 3) = antilog(2)
x = (antilog(2) - 3)/3
x ≈ 32.3333
For y-intercept,
x = 0,
y = log(3) - 2
y ≈ -1.5228
juliendelgado

Answer:

x-intercept= -1.33

y-intercept= 2.60

Step-by-step explanation:

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