Answer: y = 7, y = -1
Step-by-step explanation:
Since both A and B lie on the circle, their distances to the origin is the radius which will be equal.
[tex]d_{AO}=\sqrt{(-1-2)^2+(y + 3y)^2}\\d_{BO}=\sqrt{(5 - 2)^2+(7 + 3y)^2} \\\qquad \qquad \qquad \qquad d_{AO} = d_{BO}\\\sqrt{(-1-2)^2+(y + 3y)^2}=\sqrt{(5 - 2)^2+(7 + 3y)^2}\\\sqrt{(-3)^2+(4y)^2}=\sqrt{(3)^2+(7 + 3y)^2}\\\sqrt{9+16y^2}=\sqrt{9+(49+42y+9y^2)}\\\sqrt{9+16y^2}=\sqrt{58+42y+9y^2}\\(\sqrt{9+16y^2})^2=(\sqrt{58+42y+9y^2})^2\\\\9+16y^2=58+42y+9y^2\\7(y^2-6y-7)=0\\7(y - 7)(y + 1)=0\\y - 7 = 0 \qquad\text{and}\qquad y + 1 = 0\\\quad y = 7 \qquad \text{and}\qquad y = -1[/tex]
