The probability that a student at certain high school likes art is 36%. The probability that a student who likes art also likes science is 21%. Find the probability that a student chosen at random likes science given that he or she likes art. Round to the nearest tenth of a percent.

Respuesta :

Answer: Probability that a student chose at random likes science given that he or she likes art is 58%.

Step-by-step explanation:

Since we have given that

Probability that a student at certain high school likes art =[tex]P(A)[/tex] = 36%

Probability that a student who likes art also likes science= [tex]P(A\cap S)[/tex]  = 21%

We need to find the value of probability that a student chosen at random likes science given that he or she likes art.

As we know the formula for "Conditional Probability" :

[tex]P(S\mid A)=\frac{P(A\cap S)}{P(A)}\\\\P(S\mid A)=\frac{21}{36}\\\\P(S\mid A)=0.58\\\\P(S\mid A)=58\%[/tex]

Hence, Probability that a student chose at random likes science given that he or she likes art is 58%.


Answer with explanation:

A= Art

S= Science

P(A)= 36%

P (A ∩ S)=21%

We have to find ,[tex]P(\frac{S}{A})[/tex].

[tex]P(\frac{S}{A})=\frac{P(S\cap A)}{P(A)}\\\\P(\frac{S}{A})=\frac{\frac{21}{100}}{\frac{36}{100}}\\\\P(\frac{S}{A})=\frac{21}{36}=\frac{7}{12}[/tex]

In terms of Percentage , Required Probability

  [tex]=\frac{7}{12}\times 100\\\\=58.34[/tex]

= 58.34 %