Answer:
210/11 square units
Step-by-step explanation:
Given that in a quadrilatral KLMN,
LM ∥ KN , KL ∥ NM , h1=5, h2=6,
and the perimeter of KLMN is 42.
Since opposite sides are given to be parallel, the quad has to be a parallelogram.
Parallelogram has sides l and w (say)
Then area of parallelogram = base x height
=l(5)=w(6) ... i
Perimeter =2l+2w=42 ... ii
Multiply equation II by 3
6l+6w=42
Substitute for w from i
6l+5l=42
l=42/11
Area = 42/11(5) = 210/11 square units
