tylorroundy
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What is the equation of a line, in point-slope form, that passes through (−4, 1) and has a slope of (5,7) ?
y−1=56(x+8)
y+1=56(x−8)
y+8=56(x−1)
y−8=56(x+1)

Respuesta :

gmany

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

the point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

We have the points (-4, 1) and (5, 7). Substitute:

[tex]m=\dfrac{7-1}{5-(-4)}=\dfrac{6}{9}=\dfrac{2}{3}\\\\y-1=\dfrac{2}{3}(x-(-4))\\\\\boxed{y-1=\dfra{2}{3}(x+4)}[/tex]

Answer:

y-1=2/3(x+4)

Step-by-step explanation:

the other ans has a typo @ its last step but right everything else

it is not one of ur choices

the nearest is y−1=56(x+8) as it has the term "y-1"

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