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A spinner Has 10 equally sized sections eight of which are gray and 2 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray in the second spin lands blue

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tramserran

Answer: [tex]\frac{4}{25}[/tex]

Step-by-step explanation:

first spin    and     second spin

   [tex]\frac{8}{10}[/tex]         x           [tex]\frac{2}{10}[/tex]

= [tex]\frac{16}{100}[/tex]

= [tex]\frac{4}{25}[/tex]

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