Answer:
Please check attached graph.
Step-by-step explanation:
Graph for the answer choices are missing but still we can solve this problem.
We can create graph of y=-x-3 first
then shade the graph for given inequality.
Comparing y=-x-3 with y=mx+b gives slope m=-1 and y-intercept b=-3
so we graph a point at (0,-3) for y-intercept.
then move the point 1 unit down and 1 unit right to reach point (1,-4)
Now join both points by a solid line because of equal sign of >=
this will give graph of y=-x-3
Now we determine direction of shading using any test point which is not on the line y=-x-3
say (0,0) is test point as it is not on the line y=-x-3
plug the test point into original inequality
[tex]y\ge-x-3[/tex]
[tex]0\ge-0-3[/tex]
[tex]0\ge-3[/tex]
which is true so the direction of shading will be in the direction of test point.
