Answer
Answer
The speedometer is likely to show the speed is either 36.0 mph or 44.0 mph.
To prove
Formula
[tex]Percentage\ error = \frac{error\times 100}{Exact\ value}[/tex]
Where error = |Approx value - Exact value |
First case
As given
A speedometer has a percent error of 10%. The actual speed of the car is 40 mph.
Here
Percentage error = 10%
Exact value = 40 mph
error = - (Approx value - Exact value )
= - (Approx value - 40 )
= - Approx value + 40
Put in the formula
[tex]10 = \frac{(-Approx\ value + 40)\times 100}{40}[/tex]
[tex]400 = {(-Approx\ value + 40)\times 100}[/tex]
[tex]\frac{400}{100} =-Approx\ value + 40[/tex]
[tex]\4 =-Approx\ value + 40[/tex]
Thus
Approx value = 40 - 4
Approx value = 36 mph
Therefore Option (b) is correct .
Second Case
error = (Approx value - Exact value )
= (Approx value - 40 )
= Approx value - 40
Put in the formula
[tex]10 = \frac{(Approx\ value - 40)\times 100}{40}[/tex]
[tex]400 = {(Approx\ value - 40)\times 100}[/tex]
[tex]\frac{400}{100} = Approx\ value - 40[/tex]
[tex]\4 = Approx\ value - 40[/tex]
Thus
Approx value = 40 + 4
Approx value = 44 mph
Therefore Option (c) is correct .
Answer:
First one is B, and the third one is C.
Step-by-step explanation:
I took the K-12 quiz.
