[tex]3\dfrac{1}{3}-2\dfrac{5}{6}[/tex]
Find the common denominator
LCM(3, 6) = 6
[tex]3\dfrac{1}{3}=3\dfrac{1\cdot2}{3\cdot2}=\3\dfrac{2}{6}\\\\3\dfrac{1}{3}-2\dfrac{5}{6}=3\dfrac{2}{6}-2\dfrac{5}{6}=2\dfrac{6+2}{6}-2\dfrac{5}{6}=2\dfrac{8}{6}-2\dfrac{5}{6}=(2-2)+\left(\dfrac{8}{6}-\dfrac{5}{6}\right)\\\\=\dfrac{8-5}{6}=\dfrac{3}{6}=\dfrac{3:3}{6:3}=\boxed{\dfrac{1}{2}}[/tex]
