Answer:
The volume will be 27 times larger.
The height will be 12 units.
The area of the base will be 9 times larger.
Step-by-step explanation:
[tex]r = 3, h = 4\\V_{initial} = \pi r^2 h = 36\pi\ unit^3[/tex]
Initial diameter = 2r = 6
The area of the basis is [tex]A_{basis} =\pi r^2 =9\pi[/tex]
Now, let [tex]h_2 = 3h =3(4) = 12[/tex], and [tex]r_2 = 3r = 9[/tex]
[tex]V_{change} = \pi r_2^2 h_2 = (81 \times 12) \pi = 27 V_{initial}[/tex]
The area of the basis [tex]A_2 = \pi r_2^2 = 81\pi = 9 A[/tex].
Diamter = 2 (9) = 18
