Identify the focus and directrix of the parabola whose equation is (y-4)^2 = -12(x-7)

Answer : Focus (4,4) , directrix x=10
Given equation is
[tex](y-4)^2 = -12(x-7)[/tex]
The given equation is in the form of
[tex](y-k)^2 = 4p(x-h)[/tex]
Where vertex is (h,k)
h = 7 and k = 4 so vertex is (7,4)
4p = -12 so p = -3
Focus is (h+p, k)
h=7, k=4 and p = -3
focus is (7-3, 4) that is (4,4)
now we find directrix
Directrix x= h-p
So x= 7-(-3)= 10
Focus (4,4) , directrix x=10